MHT CET Percentile 2025 is calculated by the Number of candidates with a raw score less than or equal to your raw score divided by Total number of candidates multiplied by 100. Refer to the article to get detailed information on How percentile is calculated in MHT CET 2025.
How percentile is calculated in MHT CET 2025:
The Maharashtra CET Cell releases the MHT CET result in the form of MHT CET 2025 percentile. Candidates who will be appearing in the
MHT CET 2025
exam might be wondering how the MHT CET percentile is prepared, What is the percentile? What rank do candidates get with a certain percentile, etc? In this article, we have discussed how percentile is calculated in MHT CET 2025 exam, which will help you understand the process.
MHT CET percentile
= (100 * Number of candidates with a raw score less than or equal to your raw score) ÷ (Total number of candidates).
Candidates who will score good percentile in MHT CET 2025 exam will get admission into top
MHT CET participating colleges 2025
. Read the full article to find out how percentile is calculated in MHT CET 2025 exam, the MHT CET normalisation process, MHT CET 2025 marks vs percentile, etc, and other important information.
Latest Updates
The CET Cell concluded the rescheduled exam on May 5, 2025 for the PCM group. The MHT CET provisional answer key will soon be made available on the official website by CET Cell. Candidates will have the opportunity to object to the provisional answer key when the MHT CET answer key objection tracker window opens in conjunction with the release of the MHT CET provisional answer key. The MHT CET answer key is expected to be made available in May 2025.
How to calculate MHT CET Percentile 2025?
The MHT CET 2025 percentile score of a candidate is computed as follows:
(100 * Number of candidates in the session with a raw score equal to or less than the candidate's score) ÷ Total number of candidates in the session |
|---|
Please keep in mind that the Total MHT CET 2025 percentile should NOT be an aggregation or average of the individual subject's Percentile. The percentage gained from the marks is not the same as the percentile score.
What is MHT CET Normalisation Method?
To know more about the MHT CET 2024 normalisation method, go through the steps given below.
Step 1: Divide Applicants into two days and two shifts every day.
Candidates would be randomly assigned to four sessions, with approximately the same number of candidates in each session. These four sessions will be as follows:
- Day 1 Shift 1 Session
- Day 1 Shift 2 Session 2
- Shift-1, Day 2 Session 3
- Day-2 Shift-2 Session 4
If a greater number of days or shifts is required, the applicants will be divided proportionally. It will ensure that there is no difference in the distribution of applicants who will take the exam. Furthermore, the likelihood of such bias diminishes with a large population of examinees scattered around the country.
Step 2: Prepare the results for each session
Every session's MHT CET result 2025 will be in the form of:
Raw Scores Percentiles Scores for each subject (Mathematics, Physics, and Chemistry), as well as the overall. The four percentiles listed above will be determined for each applicant in the Session.
Let T1,M1, P1, C1 be a candidate's raw Total, Mathematics, Physics, Chemistry scores, and T1P, M1P, P1P, C1P be that candidate's Percentile Total, Mathematics, Physics, Chemistry scores.
- Total Percentile (T1P) = 100 x Total number of applicants in the session who had a raw score equal to or less than the T1 score
- Mathematics Percentile (M1P) = 100 x Number of candidates in the session who had a raw score equal to or less than the M1 in Mathematics Total number of candidates in the session
- Physics Percentile (P1P) = 100 x The number of candidates in the session who had a raw score equal to or less than the P1 score in Physics Total number of candidates in the session
- Chemistry Percentile (C1P) = 100 x the number of candidates in the session who had a raw score equal to or less than the C1 score in Chemistry. The total number of applicants who participated in the session
Step 3: Compilation of total MHT CET 2025 scores
The MHT CET percentile scores for the Total Raw Score, which is determined through Step 2 for each of the four sessions (Session 1: Day-1 Shift-1, Session 2: Day-1 Shift-2, Session 3: Day-2 Shift-1, and Session 4: Day-2 Shift-2) will be combined. This will be referred to as the CET score, which will subsequently be used to compile the results.
MHT CET 2025 Marks Vs Percentile
The MHT CET marks vs percentile 2025 analysis help candidates know what percentile candidate will get corresponding to the marks they scored in the MHT CET exam. We have provided the MHT CET 2025 marks vs percentile vs rank analysis below as per the trends.
MHT CET Marks 2024 | MHT CET Percentile 2025 |
|---|---|
160+ | Above 99.50 |
150-160 | Above 99.00 |
130-150 | 98.00-99.00 |
110-140 | 96.00-98.00 |
100-110 | 95.00-96.00 |
If you are looking for admission into the Top Private Engineering Colleges In India 2025 across the country, you can just fill Common Application Form on our website. It is a single application form for admission into various universities. We hope the above information was helpful. For more updates on How Percentile is Calculated in MHT CET?, check out our official website www.collegedekho.com
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FAQs
The percentile for 50 marks in MHT CET 2025 exam is around 55 to 65+ percentile.
Candidates with 70 percentile in MHT CET will get around 52,521 to 53,200 rank.
Candidates with 95 percentile will get a rank less than 9,145.
Candidates with 82 percentile will get around 32,171 to 33,005 MHT CET 2025 rank.
The formulae for MHT CET percentile calculation is Percentile = (100*Number of candidates with a raw score less than or equal to your raw score) ÷ (Total number of candidates).
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